What is the transformer formula?
The ideal transformer equation is Vp ÷ Vs = Np ÷ Ns = Is ÷ Ip: voltage scales with the turns and current scales the other way. With no losses, power in equals power out, so Vp × Ip = Vs × Is.
A transformer calculator for the turns ratio, secondary voltage and current, primary current, VA rating and reflected impedance. Add efficiency and regulation when you are working from a real part rather than the ideal model.
100 % is the ideal transformer.
Voltage rise from full load to no load, as % of full load. From the datasheet.
Secondary voltage
12 V
Sine waves at the rated frequency. Primary current is the load component at unity power factor; real parts add a magnetizing current, typically 1 to 5 % of rated.
Each side
| Primary | Secondary | |
|---|---|---|
| Voltage | 120 V | 12 V |
| Current | 200 mA | 2 A |
| VA | 24 VA | 24 VA |
| Impedance | 600 Ω | 6 Ω |
Multiply the primary voltage by Ns ÷ Np, and divide the secondary load’s VA by the primary voltage for the primary current. A 1000:100 transformer on 120 V gives 12 V on the secondary. Loaded with 2 A, it delivers 24 VA and draws 200 mA from the primary.
The same flux links both windings, so each turn sees the same voltage. With no losses, power in equals power out.
Impedance transforms by the square of the turns ratio, because voltage goes up as current goes down:
The VA rating is the same on both sides for the ideal part. Efficiency η scales the primary current:
Regulation is expressed against the full-load voltage, so the loaded secondary is below the turns-ratio value:
The ratio is a = 1000 ÷ 100 = 10, so Vs = 120 ÷ 10 = 12 V. With 2 A on the secondary, the load is 24 VA and 6 Ω, the primary draws 200 mA, and the load looks like 600 Ω from the primary: 120 V ÷ 200 mA gives the same number.
A 24 V full-load target with 10 % regulation needs 26.4 V at no load, so the ratio is a = 8.712. With 1150 primary turns, the secondary needs 132 turns, which delivers 24 V at load. Full load is 2.08 A on the secondary and, at 90 % efficiency, 242 mA on the primary.
a = √(3200 ÷ 8) = 20, so a 20:1 transformer makes the 8 Ω speaker look like 3.2 kΩ to the amplifier.
What a given Np ÷ Ns does to a 120 V primary and a 50 Ω secondary load. For other ratios, use the transformer turns ratio calculator at the top of the page.
| Np ÷ Ns | Secondary from 120 V | Current ratio Is ÷ Ip | Impedance ratio | 50 Ω load seen at primary |
|---|---|---|---|---|
| 100:1 | 1.2 V | 100× | 10000× | 500 kΩ |
| 20:1 | 6 V | 20× | 400× | 20 kΩ |
| 10:1 | 12 V | 10× | 100× | 5 kΩ |
| 5:1 | 24 V | 5× | 25× | 1.25 kΩ |
| 2:1 | 60 V | 2× | 4× | 200 Ω |
| 1:1 | 120 V | 1× | 1× | 50 Ω |
| 1:2 | 240 V | 0.5× | 0.25× | 12.5 Ω |
| 1:10 | 1.2 kV | 0.1× | 0.01× | 500 mΩ |
Ideal turns ratio and full-load currents for common mains and secondary combinations. The VA rating tab above gives the currents for any other pair of voltages.
| Primary | Secondary | VA | Turns ratio | Secondary current | Primary current |
|---|---|---|---|---|---|
| 120 V | 5 V | 10 | 24:1 | 2 A | 83.3 mA |
| 120 V | 12 V | 24 | 10:1 | 2 A | 200 mA |
| 120 V | 24 V | 48 | 5:1 | 2 A | 400 mA |
| 230 V | 12 V | 24 | 19.17:1 | 2 A | 104 mA |
| 230 V | 24 V | 50 | 9.583:1 | 2.08 A | 217 mA |
| 230 V | 48 V | 100 | 4.792:1 | 2.08 A | 435 mA |
The ideal transformer equation is Vp ÷ Vs = Np ÷ Ns = Is ÷ Ip: voltage scales with the turns and current scales the other way. With no losses, power in equals power out, so Vp × Ip = Vs × Is.
Divide the primary turns by the secondary turns, or equivalently the primary voltage by the secondary voltage. The transformer turns ratio formula is a = Np ÷ Ns = Vp ÷ Vs, so a 120 V to 12 V transformer is 10:1, and 230 V to 24 V is 9.583:1.
Opposite to the voltage. A 10:1 step-down transformer with 2 A in the secondary draws 200 mA from a 120 V primary, ignoring magnetizing current and losses.
Zp = a² × ZL, where ZL is the load on the secondary and Zp is how it looks from the primary. Through a 10:1 transformer a 6 Ω load looks like 600 Ω.
a = √(Zs ÷ ZL) = √(3200 ÷ 8) = 20, a 20:1 output transformer. In general the impedance ratio is the square of the turns ratio.
The product of the RMS voltage and the RMS current it can carry. It is in VA and not watts because the winding heating depends on the current regardless of the load’s power factor. Divide VA by the secondary voltage for the full-load secondary current; the VA rating tab does it for you.
Size it by VA: multiply the secondary voltage by the full-load secondary current. A 24 V secondary at 2.08 A needs 50 VA. Allow more for a rectifier load, because its narrow current pulses raise the RMS current above the DC current.
The rise from full load to no load, as a percentage of the full-load voltage. A secondary of 13.2 V with no load and 12 V at full load has 10 % regulation, so the turns are chosen to give the higher voltage.
No. Induced voltage depends on the rate of change of flux, so steady DC only produces a winding current limited by resistance, and can saturate the core.
Often less than its AC rating, because capacitor-input loads draw narrow, high-peak pulses. Hammond’s rectifier guide gives 0.62 A DC per AC amp for a bridge, 0.28 A for half-wave and 1.00 A for a center-tap winding.
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