How do you get watts from dBm?
P (W) = 10^(dBm / 10) ÷ 1000. For example 13 dBm is 10^1.3 = 19.95 mW, or 0.01995 W. Going the other way, dBm = 10 × log10(P / 1 mW).
Convert dBm to watts and back, along with dBW and milliwatts, and see the RMS, peak and peak-to-peak voltage, current and dBµV that power makes in 50 Ω, 75 Ω or any impedance. This dBm calculator starts from a power, a voltage read on a scope, or a spectrum analyzer level.
Decibels relative to 1 mW. Negative below 1 mW.
50 Ω for RF, 75 Ω for video and cable TV, 600 Ω for audio.
Power
1 mW
dBm, dBW and watts do not depend on impedance; the voltages, current and dBµV do. They assume a resistive 50 Ω load and an unmodulated sine wave.
1 mW (0 dBm) in other impedances
| Impedance | RMS voltage | Peak-to-peak (sine) | dBµV |
|---|---|---|---|
| 50 Ω | 223.6 mV | 632.5 mV | 106.99 dBµV |
| 75 Ω | 273.9 mV | 774.6 mV | 108.75 dBµV |
| 600 Ω | 774.6 mV | 2.191 V | 117.78 dBµV |
Use P (W) = 10^(dBm ÷ 10) ÷ 1000. 0 dBm is 1 mW, 10 dBm is 10 mW, 20 dBm is 100 mW and 30 dBm is 1 W. In a 50 Ω system 0 dBm is 223.6 mV rms (632.5 mV peak-to-peak for a sine), and the reverse is dBm = 10 × log10(P ÷ 1 mW).
dBm is power in decibels relative to one milliwatt. Converting to voltage needs the impedance the power is delivered into, and peak values assume a sine wave.
P = 10^(13 ÷ 10) ÷ 1000 = 19.95 mW. Into 50 Ω, Vrms = √(0.01995 × 50) = 998.8 mV, so 13 dBm is the familiar “about 1 V rms in 50 Ω”. On a scope the sine is 2.825 V peak-to-peak.
dBm = 10 × log10(100 W ÷ 1 mW) = 50 dBm, or 20 dBW. Into a 50 Ω antenna that is 70.71 V rms and 100 V peak, which is why connectors and attenuators carry voltage ratings as well as power ratings.
60 dBµV is 1 mV rms. In 50 Ω that delivers 20 nW, which is −46.99 dBm. The shortcut gives the same answer: dBm = dBµV − 106.99 in 50 Ω.
Power, RMS voltage and peak-to-peak voltage of a sine wave in a 50 Ω system.
| dBm | dBW | Power | Vrms (50 Ω) | Vpp (50 Ω, sine) | dBµV (50 Ω) |
|---|---|---|---|---|---|
| −30 dBm | −60 dBW | 1 µW | 7.071 mV | 20 mV | 76.99 dBµV |
| −20 dBm | −50 dBW | 10 µW | 22.36 mV | 63.25 mV | 86.99 dBµV |
| −10 dBm | −40 dBW | 100 µW | 70.71 mV | 200 mV | 96.99 dBµV |
| −3 dBm | −33 dBW | 501 µW | 158.3 mV | 447.7 mV | 103.99 dBµV |
| 0 dBm | −30 dBW | 1 mW | 223.6 mV | 632.5 mV | 106.99 dBµV |
| 3 dBm | −27 dBW | 2 mW | 315.9 mV | 893.4 mV | 109.99 dBµV |
| 6 dBm | −24 dBW | 3.98 mW | 446.2 mV | 1.262 V | 112.99 dBµV |
| 10 dBm | −20 dBW | 10 mW | 707.1 mV | 2 V | 116.99 dBµV |
| 13 dBm | −17 dBW | 20 mW | 998.8 mV | 2.825 V | 119.99 dBµV |
| 17 dBm | −13 dBW | 50.1 mW | 1.583 V | 4.477 V | 123.99 dBµV |
| 20 dBm | −10 dBW | 100 mW | 2.236 V | 6.325 V | 126.99 dBµV |
| 23 dBm | −7 dBW | 200 mW | 3.159 V | 8.934 V | 129.99 dBµV |
| 27 dBm | −3 dBW | 501 mW | 5.006 V | 14.16 V | 133.99 dBµV |
| 30 dBm | 0 dBW | 1 W | 7.071 V | 20 V | 136.99 dBµV |
| 33 dBm | 3 dBW | 2 W | 9.988 V | 28.25 V | 139.99 dBµV |
| 37 dBm | 7 dBW | 5.01 W | 15.83 V | 44.77 V | 143.99 dBµV |
| 40 dBm | 10 dBW | 10 W | 22.36 V | 63.25 V | 146.99 dBµV |
| 43 dBm | 13 dBW | 20 W | 31.59 V | 89.34 V | 149.99 dBµV |
| 47 dBm | 17 dBW | 50.1 W | 50.06 V | 141.6 V | 153.99 dBµV |
| 50 dBm | 20 dBW | 100 W | 70.71 V | 200 V | 156.99 dBµV |
The same 1 mW gives a different voltage in each impedance. 50 Ω is the RF standard, 75 Ω is used for video and cable TV, and 600 Ω is the old telephone and audio reference.
| Impedance | Vrms at 0 dBm | Vpp at 0 dBm (sine) | dBµV at 0 dBm | dBm at 1 V rms |
|---|---|---|---|---|
| 50 Ω | 223.6 mV | 632.5 mV | 106.99 dBµV | 13.01 dBm |
| 60 Ω | 244.9 mV | 692.8 mV | 107.78 dBµV | 12.22 dBm |
| 75 Ω | 273.9 mV | 774.6 mV | 108.75 dBµV | 11.25 dBm |
| 600 Ω | 774.6 mV | 2.191 V | 117.78 dBµV | 2.218 dBm |
The voltage columns assume an unmodulated sine wave in a matched, resistive load. Modulated signals have a higher peak voltage than a sine of the same average power: noise-like signals such as OFDM have crest factors around 11 dB, so check the peak envelope power, not just the average dBm, against an amplifier’s or analyzer’s maximum input. A mismatched load reflects part of the power, so the voltage at the connector is no longer √(P × Z). And a source with a 50 Ω output impedance driving an oscilloscope’s 1 MΩ input is effectively unloaded, so the scope can read up to twice the voltage it would develop across 50 Ω. Use the scope’s 50 Ω input or a feed-through terminator when you compare against a dBm figure.
P (W) = 10^(dBm / 10) ÷ 1000. For example 13 dBm is 10^1.3 = 19.95 mW, or 0.01995 W. Going the other way, dBm = 10 × log10(P / 1 mW).
dBm = 10 × log10(P ÷ 1 mW). For example 100 W is 10 × log10(100 W ÷ 1 mW) = 50 dBm, and 1 W is 30 dBm.
mW = 10^(dBm ÷ 10), so 0 dBm is exactly 1 mW and 13 dBm is 19.95 mW. Going the other way, dBm = 10 × log10(mW).
0 dBm is exactly 1 mW. Across 50 Ω that is 223.6 mV rms, 316.2 mV peak or 632.5 mV peak-to-peak for a sine wave, and 106.99 dBµV.
30 dBm is 1 W. Every 10 dB is a factor of ten: 20 dBm is 100 mW, 40 dBm is 10 W and −30 dBm is 1 µW. Every 3 dB is roughly a factor of two, so 33 dBm is about 2 W.
Subtract 30: dBW = dBm − 30, because 1 W is 1000 mW and 10 × log10(1000) = 30. So 30 dBm is 0 dBW, and 0 dBm is −30 dBW.
Add 30 to get dBm, then use the dBm formula. 20 dBW is 50 dBm, which is 100 W.
No. dBm is a power level, so it is the same in any impedance. The voltage it produces does depend on impedance: 0 dBm is 223.6 mV rms in 50 Ω, 273.9 mV in 75 Ω and 774.6 mV in 600 Ω.
dBµV = dBm + 90 + 10 × log10(Z). In 50 Ω that is dBm + 106.99; in 75 Ω it is dBm + 108.75. A spectrum analyzer reading of −40 dBm in 50 Ω is 66.99 dBµV.
Find the RMS voltage, Vrms = √(P × Z), then multiply by 2√2 for a sine: Vpp = 2√2 × Vrms. 10 dBm in 50 Ω is 707.1 mV rms and 2 V peak-to-peak. Modulated signals have higher peaks for the same average power.
0 dBmV is 1 mV rms. In 75 Ω that is 13.33 nW, or −48.75 dBm.
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