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Signal integrity

Lesson 38 of 411 min read

Signal integrity is about what happens when a trace stops acting like a simple wire. Every trace takes time for a signal to cross. When an edge is fast enough that it’s still rising while the wavefront travels the trace, the trace behaves as a transmission line, a structure with its own characteristic impedance, and wave effects show up: reflections, ringing, overshoot.

The counterintuitive rule is that edge rate matters, not clock rate. A humble 8 MHz microcontroller whose output drivers switch in a nanosecond produces edges with frequency content into the hundreds of megahertz, fast enough to ring on a long trace. You don’t need a high-speed design to have high-speed problems. Fast edges and enough distance will do it.

The other classic failure is crosstalk. A switching trace couples capacitively and inductively into its neighbors and leaves a copy of its signal on theirs. It gets worse with long parallel runs and tight spacing. The defenses are geometric: more space between aggressor and victim, shorter parallel runs, and a solid ground plane close underneath, which shrinks the coupling fields dramatically.

Key points

  • When edges are fast relative to trace length, traces behave as transmission lines.
  • Reflections and ringing come from impedance mismatches along the signal’s path.
  • Edge rate, not clock frequency, determines whether these effects appear.
  • Crosstalk couples between parallel traces. Spacing and a close ground plane suppress it.

Practice

0 of 2 answered · Not started

Wrong answers just let you try again, and hints are there if you want them. Answering every question first time, without hints, is what earns mastery.

  1. 1

    What decides whether a trace must be treated as a transmission line?

  2. 2

    What does a series termination resistor at the driver do?